A circle is shown on the coordinate plane below.

What is the equation of this circle?

(x + 1)2 + y2 = 2

(x – 1)2 + y2 = 4

(x + 1)2 + y2 = 4

(x – 1)2 + y2 = 2

Question

A circle is shown on the coordinate plane below.
 
  
 
What is the equation of this circle? 

 (x + 1)2 + y2 = 2 

 (x – 1)2 + y2 = 4 

 (x + 1)2 + y2 = 4 

 (x – 1)2 + y2 = 2

anonymous · Answer

attachment

anonymous · Answer

centre is (-1,0) radius is 2 units.........now can you find the equation????

anonymous · Answer

D?

amistre64 · Answer

you should prolly brush up on what a general circle equation looks like

$$(x-C_x)^2+(y-C_y)^2=r^2$$

amistre64 · Answer

so, swap signs in the center parts, and square the radius to fit

anonymous · Answer

So its B ?

amistre64 · Answer

b still has a -1 in it; try c :)

anonymous · Answer

x coordinate is -1.....y coordinate of centre is 0

radius is 2

plug in the equation
$$(x-(-1))^{2}+(y-(0))^{2}=2^{2}$$
$$(x+1)^{2}+(y)^2=4$$

anonymous · Answer

C,

anonymous · Answer

yep....do you understand or not.???? 
ask me if u didnt....

anonymous · Answer

kind of. can you explain it a little more please?

anonymous · Answer

do you know how to find the center from the graph???

anonymous · Answer

wait i think i got it.. im gonna post another question. and the answer tell me if im right or wrong

anonymous · Answer

k