Question

solve the following: 10^(2x-3) = 0.01

Answer 1

If \(a^x=b^x\), then \(a=b\). And use \(0.01=\frac1 {100}=\frac1{10^2}=10^{-2}\).

Answer 2

Oops. Really you need is that if \(a^x=a^y\) then \(x=y\).

Answer 3

Use what @klimenkov said above.
\[10^{2x - 3} = 0.01\]\[10^{2x - 3} = \frac{1}{100}\]\[10^{2x - 3} = \frac{1}{10^{2}}\]\[10^{2x - 3} = 10^{-2}\]\[2x - 3 = -2\]Solve for x now.

Answer 4

The very first statement is false. Forget it, because if \(2^2=(-2)^2\), but \(2\ne-2\).

Answer 5

What do you mean? I'm not quite following.

Answer 6

I said that mine statement was false.

Answer 7

Oh ok.

Answer 8

i'm sorry. which statement was false?

Answer 9

would the answer be x = 1/2

Answer 10

yup

Answer 11

Thanks!

Answer 12

I am so late...but you are correct :)