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Physics 8 Online
OpenStudy (anonymous):

Polly Ester and Ray Ahn are doing the Elastic Collision lab on a low-friction track. Cart A has a mass of 1.00 kg and is moving rightward at 27.6 cm/s prior to the collision with Cart B. Cart B has a mass of 0.50 kg and is moving leftward with a speed of 42.9 cm/s. After the magnetic repulsion of the two carts, Cart A is moving leftward at 10.1 cm/s. Determine the post-collision speed and direction of cart B. I don't get how to exactly solve this...i'm getting 2/3 of it, just need to know how to do the last equation/formula.

OpenStudy (nottim):

try showing a bit of you work, maybe just the general steps.

OpenStudy (anonymous):

p1=m1v1 p1=(1.00kg)(27.6cm/s) p1=10.1kg*cm/s p2=m2v2 p2=(0.50kg)(42.9cm/s) p2=21.45kg*cm/s I don't know from there.

OpenStudy (anonymous):

Polyester and Rayon., really? Why don't you conserve energy and check?

OpenStudy (anonymous):

What do you mean conserve energy? This is the conservation of momentum...

OpenStudy (anonymous):

magnetic repulsion implies that now b attains momentum of a and a attains momentum of b and both start moving in opposite direction so now P1=21.45 and P2=10.1 now divide P2 by its mass so as to calculate speed of b in opposite direction. . .

OpenStudy (anonymous):

That gives me 20.2m/s and 21.45m/s..correct?

OpenStudy (anonymous):

20.5 is direction b and is toward right. . .

OpenStudy (anonymous):

but the correct answer is 32.5 cm/s right. http://www.physicsclassroom.com/calcpad/momentum/problems.cfm number 26.

OpenStudy (anonymous):

ohk then there is a twist in the story i missed this line. . . " After the magnetic repulsion of the two carts, Cart A is moving leftward at 10.1 cm/s. " i have to make some changes now

OpenStudy (anonymous):

@some1 p1=m1v1 p1=(1.00kg)(27.6cm/s)= 27.6 "p1=10.1kg*cm/s" <----- wrong p2=m2v2 p2=(0.50kg)(42.9cm/s) p2=21.45kg*cm/s I don't know from there.

OpenStudy (anonymous):

Really sorry....I didnt read the question properly the first time. you have \[p _{Ai} + p _{Bi} = p_{Af} + p_{Bf}\] i: Initial; f: final And you know the values of pAi, pBi and pAf. pBf can subsequently be found.

OpenStudy (anonymous):

hm. i think i'll try that. thanks aish and theyatin. :D

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