Question

What are the possible number of positive, negative, and complex zeros of f(x) = –2x^3 + 5x^2 – 6x + 4 ?

Positive: 3 or 1; Negative: 1; Complex: 2 or 0

Positive: 1; Negative: 2 or 0; Complex 2 or 0

Positive: 2 or 0; Negative: 1; Complex: 2 or 0

Positive: 3 or 1; Negative: 0; Complex: 2 or 0

Answer 1

C?

Answer 2

I would say b, I find one positive root with the newton method, same with the bisection algorithm, complex roots always come in conjugate pairs, so two complex roots.

Answer 3

Adjustment: Complex roots always come in conjugate pairs when the coefficients of the polynomial are real.

Answer 4

Makes sense

Answer 5

I am glad it does (-:

Answer 6

:P Thanks