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Mathematics 22 Online
OpenStudy (konradzuse):

integral question

OpenStudy (anonymous):

integral answer

OpenStudy (konradzuse):

\[\int\limits_{1}^{\infty} \frac{1}{2x+5}\]

OpenStudy (konradzuse):

now I did u = 2x+5 1/2du = dx

OpenStudy (anonymous):

(ln(2x+5))/2 bro

OpenStudy (anonymous):

limits are 1 to infinity

OpenStudy (anonymous):

change variable: u = 2x+5 du =2dx

OpenStudy (konradzuse):

1/2 ln|2x+5| from 1 to infinitye

OpenStudy (anonymous):

divergence very much huh? (-:

OpenStudy (konradzuse):

now the question asks Confirm that the Integral Test can be applied to the series. Then use the Integral Test to determine the convergence or divergence of the series.

OpenStudy (anonymous):

The divergence test can be applied because it is a continuous function that decreases with steadily for larger values of x, because you're dividing by a larger and larger number

OpenStudy (konradzuse):

I know it doesn't diverge but it's asking me what the integral =... I tried -1/2 ln|7| and some others.

OpenStudy (anonymous):

divergence test = integral test, I sleep too less.

OpenStudy (anonymous):

well if you apply the integral method to this integral it will show you that it doesn't converge. the natural log of infinity is not defined, or rather is infinity, but log functions are slow (for computer sciences, runtime etc.)

OpenStudy (anonymous):

besides that I wouldn't know what to add.

OpenStudy (konradzuse):

Yeah I tried infinity - answer didn't work..

OpenStudy (anonymous):

it is in agreement from what I know about this function I believe that it diverges. Maybe you want to wait for another answer.

OpenStudy (konradzuse):

ok infinity worked... :p

OpenStudy (anonymous):

I hope so (-:

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