Question

8. Find the momentum of a photon in eV/c and in Kg. m/s if the wavelength is (a) 400nm ; (b) 1 Å = 0.1 nm, (c) 3 cm ; and (d) 2 nm .

Answer 1

\[p=h/\lambda\] where
\[h=?\]

Answer 2

h = plank's constant*

Answer 3

(a) I got this
\[1.656517*10^{-27}(m*kg)/s\]

Answer 4

for part two on (a) I used
\[p=E/c\] where
\[E=hc/\lambda\] and I got this answer
\[4.9*10^{-19}(eV/c)\] can I get anyone else to confirm this?

Answer 5

Look at the section on momentum:
http://en.wikipedia.org/wiki/Electron-volt
It says 1 Gev/c = 5.344 x 10^-19 kg m/s
so 1 eV/c = 5.344 x 10^-28 kg m/s

Using your answer for the first part of the question, I get
p = 3.1 eV/c