A prism has a right triangle as its base with a hypotenuse that measures 5 meters and legs that measure 3 meters and 4 meters. What is the surface area of this prism if the height of the prism is 6 meters? When I tried to do the problem, I got 102 squared and got it wrong. How do I figure it out correctly?
surface area is the sum of the individual sides's areas
so you start with the base
4*3/2 = 6
now do the vertical sides above the two legs
4 * 6/2 = 12 3 * 6/2 = 9
now do the face above the hypotenuse
there are a few ways of doing this
the easiest would probably be with trigonometric functions. Have you covered those yet?
Yes. You mean sin and cosine, right?
yes
so we know the base is 5, the harder part is finding the height.
actually, now that I think about it this method does not require trig anyway.
but whatever
xD Okay
The problem also says "What is the surface area of this prism if the height of the prism is 6 meters? " if that is height we are trying to find.
not quite
we need to find the height of the face, not of the prism
Oh, okay.
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