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\[4 = -\frac 32 (3) + b\]
is that it?
yes. i've gotten up to there but I don't understand how to find b.
how about muliplying \[-\frac 32 \times 3\] first?
what do you get?
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-9/2?
right
You need to do the opposite and change sides on each side to isolate b.
\[4 = -\frac 92 + b\] now add \(\frac 92\) to both sides \[4 + \frac 92 = -\frac 92 + \frac 92 + b\] got it?
O_O
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lol that right side is just 0 dont be intimidated
i just showed it step-by-step
\[4 + \frac 92 = b\] now do you get it?
Calc, what is \[9/2 - 9/2\]
0...
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Okay, so what are you left with?
Igb, how do you put a number over a number? I can't find that option in the equation editor.
@lgbasallote
\frac{numerator}{denominator} put that in equation editor
Thanks
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