\[e^{-x}=5\] does this look better? or maybe
\[e^{x}= \frac{1}{5}\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
The natural log will cancel the e and bring down the x
OpenStudy (anonymous):
You understand?
OpenStudy (anonymous):
so the answer would be ln(1/5) ?
OpenStudy (lgbasallote):
haha so many answers
OpenStudy (anonymous):
Yes that is the answer. You can simplify it however you want. I would just leave it as that.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
okay thank you. that makes sense!
OpenStudy (zzr0ck3r):
notice that 1/5 = 5^(-1) and a property of logs is a*log(b) = log(b^a) so log(1/5) = log(5^(-1)) = -1*log(5) this is the great thing about logs, you can really "play around" with them. notice how i got to the same thing two compelety different ways.