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evaluate this integral ∫x-1/x dx
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\[\int \frac{x-1}{x}dx\] is that it?
yup :)
\[\int \frac{x-1}{x}dx \implies \int \frac{x}{x}dx - \frac{1}{x}dx \implies \int dx - \int \frac 1x dx\] does that help?
maybe i should write it more beautifully \[\int dx - \int \frac{dx}{x}\] heh
the answer will be -In|x| ?
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that's just \[-\int \frac{dx}{x}\]
what about \[\int dx\]
doesnt x/x cancel out ?
it becomes 1
do \[\int \frac xxdx \implies \int dx\]
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so*
oh okay got it! thank you :)
also dont forget +C
since it's indefinite integral
oh yeah
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