Question

Circle S has an equation of (x – 16)2 + (y – 9)2 = 4. What is the center and radius of circle S?

Answer 1

@Calcmathlete

Answer 2

General equation of circle is given as:

\[(x-h)^2 + (y - k) ^2 = r^2\]

Can you find h and k by comparing it with the equation given??

Answer 3

The form of a circle is:
\[(x - h)^{2} + (y - k)^2 = r^2\]THe center is (-h, -k) and the radius is r. Can you see if you can figure it out?

Answer 4

not too sure how to use that

Answer 5

Alright.
\[(x - 16)^2 + (y - 9)^2 = 4\]For the center, set each equal to zero.
x - 16 = 0

y - 9 = 0

Can you solve for x and y individually?

Answer 6

16 and 9

Answer 7

You have to just compare the two equations..

What is in place of h and k in your equation??

Answer 8

Yes you are right it is 16 and 9..

So, (16,9) will be the center..

Answer 9

and the radius is 2?

Answer 10

Yes :)

Answer 11

Yes very correct..

Answer 12

thanks!!!

Answer 13

Welcome dear..