Question

evaluate this integral
∫x^2 +1 /x^2+3x+2 dx

Answer 1

have you tried dividing the polynomial?

Answer 2

I did long division and got 1 -3x-1/x^2+3x+2

Answer 3

you mean \[\int (1 - \frac{3x - 1}{x^2+3x+2})dx\]
right?

Answer 4

yea thats right

Answer 5

split it up \[\int dx - \int \frac{3x-1}{x^2 + 3x +2}dx\]
first one is simple
second one is solveable by partial fractions

Answer 6

oh yeah, i got it now thanks. I was actually trying to solve the second one using the substitution thats why i was getting the right answer.

Answer 7

haha congrats :D