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Mathematics 7 Online
OpenStudy (anonymous):

How will you Prove Mathematically: In case of Parallel Lines, the Slopes of the two are equal that is : \(\color{green}{m_1 = m_2}\) And in case of Perpendicular Lines, the Slopes of the two are negative reciprocals of one another or you can say their Product is \(-1\) that is : \(\color{blue}{m_1m_2 = -1}\)..

OpenStudy (ash2326):

Slope of a line is also the tangent of the angle it makes with the x- axis here \[\tan \theta_1=m_1\]|dw:1342755727241:dw| and \[\tan \theta_2=m_2\] If the two lines are parallel, then they will make equal angle with x-axis, \[\theta_1=\theta_2\] taking tangent both sides \[\tan\theta_1=\tan \theta_2\] so \[m_1=m_2\]

OpenStudy (anonymous):

Isn't the proof graphical??

OpenStudy (ash2326):

Nope, it's analytical I just made the figure to show the angles

OpenStudy (anonymous):

Is there difference between analytical and Mathematical??

OpenStudy (anonymous):

Actually I have one formula from which I can prove the above..

OpenStudy (ash2326):

Here both are the same, :) I think you could use the formula

OpenStudy (anonymous):

By mathematical we mean using formula, no???

OpenStudy (ash2326):

I guess

OpenStudy (anonymous):

The formula says: The angle between the two lines is given by: \[\large \color{blue}{\tan(\theta) = \frac{|m_1-m_2|}{1 + m_1 m_2}}\] |dw:1342756469713:dw|

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