Ask
your own question, for FREE!
Mathematics
13 Online
OpenStudy (anonymous):
solve for x
cos(5x)+cos(2x)=0
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
use cosA+cosB identity
OpenStudy (anonymous):
\[x = 2 (\pi n-\tan^(-1)(\sqrt(5/3-(2 (1+i \sqrt(3)))/(3 (1/14 (13+3 i \sqrt(3)))^(1/3))-1/3 2^(2/3) (1-i \sqrt(3)) (1/7 (13+3 i \sqrt(3)))^(1/3))))\]
OpenStudy (anonymous):
i only know the identity of cos(A+B)
OpenStudy (anonymous):
tell me what cos(A+B)+cos(A-B) is
OpenStudy (anonymous):
so you mean B=0?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
nope
just tell me what you get by using the formulae
OpenStudy (anonymous):
cos(A)cos(B)-sin(A)sin(B)+cos(A)cos(B)+sin(A)sin(B)
OpenStudy (anonymous):
=2cos(A)cos(B) right?
OpenStudy (anonymous):
=> cos(5x)cos(2x)=0
OpenStudy (anonymous):
no dont jump to conclusions
now put A+B=x and A-B=y
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
which means A=(x+y)/2 and B=(x-y)/2
OpenStudy (anonymous):
now, what you get by cosx+cos y
OpenStudy (anonymous):
why need the set A and x?
OpenStudy (anonymous):
i am trying to get you to the formula. this x is not the x in the problem. instead its a general variable.
OpenStudy (anonymous):
would you mind to give me all steps and lead it to the
answer Pi/7 + 4pi/7 k, 3pi/7+ 4pi/7 k, pi/3 + 4pi/3 k
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
x=pi/3
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Twaylor:
test post
4 days ago
9 Replies
0 Medals