solve for x cos(5x)+cos(2x)=0
use cosA+cosB identity
\[x = 2 (\pi n-\tan^(-1)(\sqrt(5/3-(2 (1+i \sqrt(3)))/(3 (1/14 (13+3 i \sqrt(3)))^(1/3))-1/3 2^(2/3) (1-i \sqrt(3)) (1/7 (13+3 i \sqrt(3)))^(1/3))))\]
i only know the identity of cos(A+B)
tell me what cos(A+B)+cos(A-B) is
so you mean B=0?
nope just tell me what you get by using the formulae
cos(A)cos(B)-sin(A)sin(B)+cos(A)cos(B)+sin(A)sin(B)
=2cos(A)cos(B) right?
=> cos(5x)cos(2x)=0
no dont jump to conclusions now put A+B=x and A-B=y
which means A=(x+y)/2 and B=(x-y)/2
now, what you get by cosx+cos y
why need the set A and x?
i am trying to get you to the formula. this x is not the x in the problem. instead its a general variable.
would you mind to give me all steps and lead it to the answer Pi/7 + 4pi/7 k, 3pi/7+ 4pi/7 k, pi/3 + 4pi/3 k
x=pi/3
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