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Find the Maclaurin expansion of cos(x^3)
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So i'm thinking since it's Maclaurin a = 0. I know the Maclaurin expansion of cos(x) = SUM(-1)^n * (x^(2n))/(2n)!
replace x with x^3
why would we just do that ? if it was asking for the maclaurin expansion of x cos (x) i would just multiply the expansion of cos(x) by x. So wouldn't I need to multiply it by something again or do some computation to the orignal expansion besides just replacing x ?
just replacing
for example u know that \( \frac{1}{1-x}=1+x+x^2+... \) for |x|<1 now for \( \frac{1}{1-x^2}\) u just need to replace x with x^2 to get \( \frac{1}{1-x^2}=1+x^2+x^4+... \)
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oh wow. I get it now. sorry for making you have to type up those equations. Thanks though!
welcome my friend
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