which of the following has an incomplete octet in the lewis structure? A) \(SO_2\) B) \(ICl\) C) \(CO_2\) D) \(F_2\) E) \(NO\) how to get it?
Lewis' structure draws only the last electronic ring.
Need to go sleep, @waterineyes can handle this lol :P
Yes I will @zepp Good Night and have Sweet Dreams..
Try to draw the lewis structures for all the compounds given.. Firstly check for the valence electrons in each case...
uhmm?
Should I explain more??
Valence Electrons: Sulphur has 6, Oxygen has 6, Iodine has 7, Chlorine has 7, Carbon has 4, Florine has 7, Nitrogen has 5.. The trick is to check for the Odd Valence Electrons..
wait...
what des incomplete octet mean first
does*
Octet means 8.. If any element or atom like S on pairing does not able to have 8 electrons on it then it is called Incomplete Octet...
My English is not very good.. but i will explain it better by drawing..
when there's a lone pair then it's an incomplete octet?
no........
Sorry,, I got a call..
Yes @lgbasallote you can say that.. See, In Sulphur, there are 6 valence electrons.. it has incomplete octet.. So, how many electrons are needed to complete the octet??
What silly question I am asking to 99SS student..
it needs 2 electrons right?
See, In SO2, there are 18 valence electrons(6 + 6 + 6) So.. Compounds having Even valence electrons have generally complete octet.. So, It is having the complete octet.. Now tell me like this which compound has odd number of valence electrons??
Yes you are right lgba it needs 2 electrons to complete its octet.. Now when you attach 2 oxygen atoms with Sulphur you get: |dw:1342772196869:dw|
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