Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
when you have an absolute value you can write it as such and solve
-9<x+5<9
OpenStudy (compassionate):
IxI<4 = x<4
OpenStudy (anonymous):
wrong it's x+5<9 or x+5>-9
OpenStudy (compassionate):
No it's not.
OpenStudy (compassionate):
You always solve on the variable side.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
does it make any sense to solve
x+5<9 and x+5<-9....if you already know that x+5<9
OpenStudy (anonymous):
and that isn't correct compassionate you're completely disregarding the absolute value
OpenStudy (compassionate):
Please explain how you solved it. I seem to be misconstruing the information
OpenStudy (anonymous):
-9<x+5<9
if you subtract 5 to both sides you get
-14<x<4
which is the same as
x>-14 and x<4
OpenStudy (anonymous):
Case1
x<-5
then, Ix+5I=-(x+5)
so,
-x-5<9
-x<14
x>-14
but x<-5
therefore , x belongs to (-14,-5)..........................1
Case2,
x>-5
then, Ix+5I=x+5
x+5<9
x<4
but x>-5
so, x belongs to (-5,4)...............2
union of 1 and 2 is the soution.
x belongs to (-14,-5)U(-5,4)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (compassionate):
I said x<4...
OpenStudy (compassionate):
INB4 @higgs
OpenStudy (anonymous):
lol @Compassionate
Maybe drawing the graph might help
|dw:1342774636391:dw|