...
when you have an absolute value you can write it as such and solve -9<x+5<9
IxI<4 = x<4
wrong it's x+5<9 or x+5>-9
No it's not.
You always solve on the variable side.
does it make any sense to solve x+5<9 and x+5<-9....if you already know that x+5<9
and that isn't correct compassionate you're completely disregarding the absolute value
Please explain how you solved it. I seem to be misconstruing the information
-9<x+5<9 if you subtract 5 to both sides you get -14<x<4 which is the same as x>-14 and x<4
Case1 x<-5 then, Ix+5I=-(x+5) so, -x-5<9 -x<14 x>-14 but x<-5 therefore , x belongs to (-14,-5)..........................1 Case2, x>-5 then, Ix+5I=x+5 x+5<9 x<4 but x>-5 so, x belongs to (-5,4)...............2 union of 1 and 2 is the soution. x belongs to (-14,-5)U(-5,4)
I said x<4...
INB4 @higgs
lol @Compassionate Maybe drawing the graph might help |dw:1342774636391:dw|
Join our real-time social learning platform and learn together with your friends!