Ask
your own question, for FREE!
Mathematics
13 Online
OpenStudy (moongazer):
How do you get the quotient of this.
(x^6+y^6 )÷(x+y)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
i dont think it's factorable :/ you'll have to go with long division sorry
OpenStudy (anonymous):
Ha ha ha..
After a long struggle you wrote this??
OpenStudy (anonymous):
You can get..
OpenStudy (lgbasallote):
hmm it's complicated with long division too
OpenStudy (moongazer):
What should I do?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
See,
\[(x^2)^3 + (y^2)^3 = (x^2+y^2)(x^4 + y^4 - x^2y^2)\]
OpenStudy (moongazer):
I got that one. That is from the sum of two cubes.
but what should I do next?
OpenStudy (anonymous):
I am not finding any strong way to do that..
But let me go by long division method..
OpenStudy (moongazer):
did you got something?
OpenStudy (anonymous):
\[\large \color{green}{Quotient = x^5 -x^4y + x^3y^2-x^2y^3 + xy^4 - y^5}\]
And,
\[\large \color{blue}{Remainder = 2y^6}\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I found this by using Long Division Method..
I think it could be more simpler to solve this if it was:
\(x^6 - y^6\)
OpenStudy (moongazer):
How did you divide it?
OpenStudy (anonymous):
It is a long division method..
How can I show you I am not getting..
OpenStudy (moongazer):
could you please show me step by step on how did you get the quotient.
please... :)
OpenStudy (moongazer):
@waterineyes
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I show you step by step but It may take time..
OpenStudy (moongazer):
Thank you :)
OpenStudy (moongazer):
I am really confused with this :)
OpenStudy (anonymous):
|dw:1342783178254:dw|
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Twaylor:
test post
4 days ago
9 Replies
0 Medals