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\[\int\limits \frac{x}{x ^{2}+6x}dx\]
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Nevermind I should read more carefully, this identity is equal to \[\frac{1}{x+6}\]
how???
So you will get \[ \large \int \frac{1}{x+6} dx = \ln |x+6| +C\]
\[ \frac{x}{x^2+6}=\frac{x}{x(x+6)}=\frac{1}{x+6}\]
the first one should be x^2+6x
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thanks. :)
welcome
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