How can I solve,
A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. What is the maximum height of the particle?

Question

How can I solve, 
A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. What is the maximum height of the particle?

zzr0ck3r · Answer

I forget all the equations, post this in the physics section and you will get help faster I bet

anonymous · Answer

At a cursory glance, the maximum height is 96ft. The problem needs more information. Speed of 16ft/s in what direction/angle? Are we assuming that we're on earth?

anonymous · Answer

H(t) = -16t^2 + vt + s is the formula?

anonymous · Answer

For parabolic motion, the maximum height is the time at which d/dt = 0

anonymous · Answer

You should also account for any constants, such as the initial height. This is a question better left for the physics section. If you are not in classical (calculus physics) that answer may make no sense.

zzr0ck3r · Answer

yes orphtroll I think that is what they are asking. plug in height and v, the take dervative and set it equal to 0, or use the vertex formula.

zzr0ck3r · Answer

g is not considered

anonymous · Answer

So first take the derivative of the function. Set it equal to 0, this will give you a time. You can go back in and plug that time back in to the original equation with any constants and arrive at a max height.