Rewrite the following differential equation as an equivalent system of first-order differential equations. Use the variables x1=x x2=x' x3=x'', etc. (so that your equations will have the form x2'=x3, etc.: denote subscripts by appending the subscript to the variable name: X1= x1) Equation to rewrite: x''''+20x''−13x'+17x=−5cos(9t) x1' = x2' = x3' = x4' =
\(x _{1} = x\) \(x _{2} = x'\) \(x _{3} = x''\) \(x _{4} = x'''\) \(x _{5} = x''''\)
how do solve for those values though
Im not exactly sure... I know they are saying that \[x _{2}'=x'' = x _{3}\]
yea i got that too but im not sure what else were supposed to be doing ijn order to get those values
im gunna go read a little and try and figure this out. maybe by that time someone like @TuringTest or @dpaInc can help you
ok thank you and I will continue reading as well
what is the section of your diffs book that this cam from titled?
it wasn't from my book it was from an online web homework site and ive been looking in the book for similar problems and can't find it
but i assume it has something to do with first-order systems
is this the first one in the homework?
yes
Simply rearranging we can say this: \(x''''=-20x''+13x'-17x−5\cos(9t)\) Then using what we said earlier: \(x_{4}' = -20x''+13x'-17x−5\cos(9t)\)
But now we are second order
i do not think thats what its asking. I do believe it is first order systems
so: \[x_{4}' = -20x_{2}'+13x'-17x−5\cos(9t)\]
and your system also includes these equations:
yes but i think what we're supposed to it is know that x''''=f(t,x,x',x'',x''') and then we use what they gave us to solve for the answers. we know that x1=x and x2=x'=x1' and x3=x''=x2' and x4=x''''=x1'''=x2''=x3'
so we get x1'=x2 x2'=x3 x3'=x4 x4'=?
\(x_{1}' = x_{2}\) \(x_{2}' = x_{3}\) \(x_{3}' = x_{4}\) \(x_{4}' =-20x_{2}'+13x'-17x−5\cos(9t) \)
do we need to substitute anything in
honestly im not exactly sure what form they want the variables of the last equation
We are definatley close tho... lol
lol yes we are thank you
In this one they put them in terms of \(x_{1}\) and \(x_{2}\) http://www.phaser.com/modules/elaydi/content/helptips/secondorderode.html
plus all the other equations are in those terms... so might as well.
ok let me try it and see what happens
woo it works!! I guess it wasnt as complicated as it seemed to be! we didhave to replace the variables
=P
yes diffs is weird stuff... just flat out weird..
yea i agree! lol
whats even weirder is that theres all sorts of natural phenomenon that somehow fit themselves into the solution to differential equations...
i know!
differential equations is a very interesting subject
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