Suppose y varies jointly as x and z. Find y when x=2and z =27, if y = 192 when x=8 and z= 6.
@moha_10 do u kno how to do this?
It is a direct variation: \[\large y = k \times (xz)\] where k is any constant.. Now you are given with y = 192 x = 8 and z = 6 can you find k from here..
@janessia atleast you should reply in case you are not getting...
im sorry i was helping my mom gosh!
hold on i maybe can find k let me try
does k=4? @waterineyes
Yes you are right.. Again use the same formula: Now you have k=4 x = 2 an d z = 27 find y..
216?
Yes this is the value of y.. Well done...
yayy! i have another question like this If y varies inversely as x and y=2 when x =25 find x when y=40. @waterineyes
In case of inverse proportion: k remains in the numerator but x or whatever is given goes to denominator like this: \[\large \color{green}{y = \frac{k}{x}}\] First of all find k by putting x = 25 and y = 2.. After that when you got k using the same formula put y = 40 and find x from there..
ohk hold on
ohk i got a big number i got 2000
what is k??
i got 50 for k
Yes now you have y = 40 and k = 50 solve for x..
why are you multiplying them:???
yes when u look for x u multiply right? cuz its being divided?
\[y = \frac{k}{x}\] \[x = \frac{k}{y}\]
ohhhhh
i got 1.25
Hurry up tell me It is 3:21 in the morning here.. I have to shut my pc down.. Yes it is 5/4 = 1.25..
Good Night janessia.. Well done....
thnk u
sorry
It is okay no need to be sorry.. Welcome dear..
:)
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