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Find the standard deviation, , for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth. n = 1765; p = 0.57
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don't you first find the variance \[\sigma = np(1-p).... or ... \sigma = npq\] then take the square root
the first one is correct i believe for standard deviation
answer is 20.80
ok... so its 1795x 0.57 x 0.43
its an age since I've done binomial distribution stuff... hope I helped
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