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Mathematics 11 Online
OpenStudy (anonymous):

Find the standard deviation, , for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth. n = 1765; p = 0.57

OpenStudy (campbell_st):

don't you first find the variance \[\sigma = np(1-p).... or ... \sigma = npq\] then take the square root

OpenStudy (anonymous):

the first one is correct i believe for standard deviation

OpenStudy (anonymous):

answer is 20.80

OpenStudy (campbell_st):

ok... so its 1795x 0.57 x 0.43

OpenStudy (campbell_st):

its an age since I've done binomial distribution stuff... hope I helped

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