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A chemist requires 0.387 mol Na2CO3 for a reaction. How many grams does this correspond to?
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@zepp
y u call me when dad calls me to go eat >.>
i got this, but just one thing...would the total mass be Na2 + C + O2 together?
what? :O nooo
>Get the molar mass of the thingy >Multiply this mass by the # of mole in the problem >Fun brb
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kk
\[.387molNa_2CO_3*\frac{2(23)+12+2(16)gramsNa_2CO_3}{1molNa_2CO_3}=.387*90\]
\[.387*90=34.83gramsNa_2CO_3\]
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