Solve the compound inequality 60 < 20u < 120. Question 1 options: 1) 3 < u < 6 2) 6 > u > 7 3) 6 < u < 3 4) 3 > u < 6
60 <20 u <120 simply divide BOTH sides by 20. what do you get?
6 ?
there must be TWO sides
sort of think of having a equal sign on both sides, so what ever you do to one part you do to all three parts, the only thing you have to do it flip the signes when you devide or multiply by a negative
what's 60/20?
3
here's an easy example so you have an idea 9 < 3x < 12 divide both sides by 3 3 < x < 4 do you get it?
i think it's not "both" sides since there are three sides heh
:)
OKAY I do . its just the signs that confuses me
hmm well in this case there's no sign change since there's no division of negative so you're safe :)
only flip them when you deal with negatives example 20<-2x<10 since we devide away the -2 we flip the signs -10>x>-5
here's an example of sign change 9 < -3x < 12 divide all sides by -3 -3> x > -4
ooo wow that's easy. im always over thinking when it comes to algebra
thank you guys
there's always room for mistakes ^_^
what about this proble. is it the same thing Solve the compound inequality 9 + 3n alt= 3 or 5n < 30
alt?
maybe rewrite that
okay nevermind. you know the sign that has > and it has a minus sign underneath
thats an equals sign just write it like <= or >= if you want
okay ill do that Solve the compound inequality 9 + 3n >= 3 or 5n < 30
remind me...is solving compound inequality any different from solving inequalities individually?
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