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Chemistry 15 Online
OpenStudy (anonymous):

What is the average mass of a single chlorine atom in grams?

OpenStudy (anonymous):

@dpaInc here

OpenStudy (anonymous):

im having lunch right now....cuz waiting for u took forever D:

OpenStudy (anonymous):

How many atoms there are in a mole?

OpenStudy (anonymous):

6.02x10^23

OpenStudy (anonymous):

Cool, what's the molar mass of chlorine?

OpenStudy (anonymous):

35.45

OpenStudy (anonymous):

Cool, so what's the mass of 1 atom of chlorine?

OpenStudy (anonymous):

take that multiply by that ?

OpenStudy (anonymous):

\[\large 1 \text{ mole}=6.023*10^{23} \text{atoms}\]

OpenStudy (anonymous):

\[\large 1 \text{ mole of chlorine}=34.45\text{g}\]

OpenStudy (anonymous):

Transitivity property; \(\large 6.023*10^{23} \text{ atoms of chlorine}=34.45\text{g of chlorine}\) Now you can do it.

OpenStudy (anonymous):

You are looking for the mass of 1 atom.

OpenStudy (anonymous):

34.45g/6.02x10^23 ??

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

5.72x10^23

OpenStudy (anonymous):

Should be \(\large 5.72*10^{-23}\)

OpenStudy (anonymous):

You probably forgot to put \(6.023∗10^{23}\) in parentheses.

OpenStudy (anonymous):

ohh so when you divide then you gotta put it in parenthesis? and when your multiply then don't need to ?

OpenStudy (anonymous):

uh oh..."You are close. Check for rounding errors, and keep four sigificant figures in your answer."

OpenStudy (anonymous):

why i put 5.723x10^-23 and it still wrong wtf o_0

OpenStudy (anonymous):

@Blitzkrieg

OpenStudy (zepp):

Lemme see

OpenStudy (anonymous):

@zepp hello?

OpenStudy (zepp):

Internet must stop lagging for nothing ;[

OpenStudy (anonymous):

i got problem with this site yesterday too, otherwise this hw would've done :(

OpenStudy (anonymous):

anyway, what to do with the 5.723x10^-23 ?

OpenStudy (zepp):

Try 5.73x10^-23

OpenStudy (anonymous):

still wrong...it said check for rounding errors and it should be 4 sig fig.

OpenStudy (anonymous):

omg chlorine is 35.45 not 34.45 zepp !! D:

OpenStudy (zepp):

zz :[

OpenStudy (anonymous):

got 80% correct for that problem.... LOL after soo many fails

OpenStudy (zepp):

>.>

OpenStudy (anonymous):

i posted 35.45 and you copied it wrong, and then i copied you and ....wrong lmao :)))

OpenStudy (zepp):

@Blitzkrieg WRONG

OpenStudy (anonymous):

triple wrong... O__O

OpenStudy (anonymous):

@Blitzkrieg bad!! Blitz!!

OpenStudy (anonymous):

What is the mass (in grams) of 9.52 × 1024 molecules of methanol (CH3OH)?

OpenStudy (anonymous):

Ahhh

OpenStudy (anonymous):

Try 5.8858 * 10^-23 then?

OpenStudy (anonymous):

i got it...already done...moving on!

OpenStudy (anonymous):

What is the mass (in grams) of 9.52 × 1024 molecules of methanol (CH3OH)?

OpenStudy (anonymous):

that's 10^24 btw

OpenStudy (zepp):

Oh cool

OpenStudy (anonymous):

oh i know how to do this

OpenStudy (anonymous):

Now it's conversion mole <-> atoms

OpenStudy (anonymous):

is it a 3 steps problem?

OpenStudy (anonymous):

first yu gotta convert from mole to mol and then from mol to grams right ?

OpenStudy (anonymous):

506 g of CH3OH ?

OpenStudy (zepp):

Mole = mol o.o

OpenStudy (zepp):

mol is just a unit for mole, abbreviation.

OpenStudy (anonymous):

oohhhh lmao =.=

OpenStudy (anonymous):

well then i guess you just take that 9.52x10^24 x avogadro's number right ?

OpenStudy (zepp):

Divide

OpenStudy (zepp):

Looks like you have an enormous difficulty to distinguish when to divide or multiply :|

OpenStudy (anonymous):

why is it divide? =.=

OpenStudy (zepp):

Number of Avagadro = # of atoms * (in) 1 mole of some substance.

OpenStudy (zepp):

\[\large 6.023*10^{23}=6.023*10^{23}*1\text{mol}\]

OpenStudy (anonymous):

please do the calculation for me.. i wanna see how u do it

OpenStudy (anonymous):

@zepp

OpenStudy (anonymous):

omg it is 506 g of CH3OH !! i got it right D:

OpenStudy (anonymous):

forget u zepp, i want Blitz back :D

OpenStudy (zepp):

Dad suddenly wants to disturb me.

OpenStudy (anonymous):

:(

OpenStudy (anonymous):

next problem: How many grams of Cl are in 285 g of CaCl2?

OpenStudy (zepp):

We did many of this kind of question, you should be able to do them easily now :(

OpenStudy (anonymous):

ok let me try, you check my answer ok? :D

OpenStudy (zepp):

alright

OpenStudy (anonymous):

is it 140 g Cl?

OpenStudy (zepp):

Put it in the box and see if you got it right or not, be self-confident :)

OpenStudy (anonymous):

D: !

OpenStudy (anonymous):

cuz i already got 4 wrong for that problem so...self confident is gone hahaha

OpenStudy (zepp):

Show steps pls

OpenStudy (anonymous):

5 wrong lol

OpenStudy (anonymous):

hold on..i got this

OpenStudy (anonymous):

|dw:1342918343366:dw|

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