How does one do this problem?

Simplify. Assume that no denominator is equal to zero.
(4g^2h^3)^3

Question

How does one do this problem?

Simplify. Assume that no denominator is equal to zero.
(4g^2h^3)^3

anonymous · Answer

Please.. help.

anonymous · Answer

Lets start off with something easy.
$$(x^6)^2$$
Do you know how to use rules of exponents to "simplify" this?

anonymous · Answer

well first you need to know how to multiply powersx power

anonymous · Answer

@agentc0re Would it be x^12

anonymous · Answer

Not quite.  Lets think of something a bit more basic.  What is $$6^2$$?

anonymous · Answer

36. :P

anonymous · Answer

.....

anonymous · Answer

Sorry my browser just crapped out and i'm gonna have to retype my answer.

anonymous · Answer

what we can see is that we can group things first to obtain the actual answer.  so in my simple example of$$(x^6)^2 = x^{(6^2)} = x^{36}$$

Now, all we have to do is do this with your problem.  Let me try and help you group everything together.
$${(4g^{(2h^3)})}^3 = {4^3g^{3(2h)^{3*3}}}$$

Remember your rules of arithmetic.  You have to do powers before multiplication.  Let me know what you get and we'll see if it's right or not and i can help better explain if need be. :D