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Mathematics 16 Online
OpenStudy (anonymous):

A catapult launches a boulder with an upward velocity of 112 ft/s. The height of the boulder, h, in feet after t seconds is given by the function . How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary.

OpenStudy (anonymous):

\[h = -16t^2 + 112t + 30\]

OpenStudy (anonymous):

differentiate h WRT t and equate it to 0 to get the maximum height and substitute it back in the equation to get the maximum height

OpenStudy (anonymous):

A. 7 s; 30 ft B. 3.5 s; 366 ft C. 3.5 s; 618 ft D. 3.5 s; 226 ft so which one would it be?

OpenStudy (anonymous):

@tngirl865 , I am sorry, I can lead you to the answer but I can't present it to you. you have to do the work. :|

OpenStudy (anonymous):

ok just help to get the answer.. I need to pass this test

OpenStudy (anonymous):

differentiate the relation wrt t and equate to 0.

OpenStudy (anonymous):

ok thanks

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