Question

Use ∆ABC to answer the question that follows.



Given: ∆ABC

Prove: The three medians of ∆ABC intersect at a common point.

When written in the correct order, the two-column proof below describes the statements and justifications for proving the three medians of a triangle all intersect in one point.

Answer 1

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1001_05/image0174e982e70.gif

Answer 2

Which is the most logical order of statements and justifications I, II, III, and IV to complete the proof?

II, III, I, IV

III, II, I, IV

II, III, IV, I

III, II, IV, I

Answer 3

@aroub

Answer 4

its not A for sure

Answer 5

C maybe?

Answer 6

No...I couldn't really understand the lesson

Answer 7

Do you know?

Answer 8

@ganeshie8 do you know how to do this?

Answer 9

It's either C or D...

Answer 10

I'm leaning more towards C though because by the midsegment theorem, you can substitute a segment on the line that's parallel... @ganeshie8 what do you think?

Answer 11

me too C !

Answer 12

thank you so much!

Answer 13

np :)

Answer 14

I need help on this also

Answer 15

II)
check triangle ABH - FG || BH
check triangle AHC - GE || HC

III)
GC is extension of FG
BG is extension of GE

Answer 16

ok above is for first q

Answer 17

@J.L. Can you just attach the screenshot rather than copying it to Word?

Answer 18

I'm not sure how to do that...sorry!

Answer 19

I'll do it then :)

Answer 20

thanks

Answer 21

@ganeshie8 Would you say B? Not seeing much wrong with this proof...

Answer 22

Oh wait, that is not the definition of parallel lines though...

Answer 23

do you need a list of all the postulates, theorems, and stuff?

Answer 24

http://learn.flvs.net/webdav/educator_geometry_v14/module10/10_list.htm

Answer 25

yeah tough to pick the wrong one

Answer 26

Well, based on the definitions that you were given, I would say B:
Parallel Lines: Two lines that lie within the same plane and never intersect. Parallel lines have the same slope.
Parallel Lines Postulate: Given a line and a point not on that line, there exists only one line through the given point parallel to the given line.

Answer 27

quick question: can you construct a midpoint? cause from what I've learned is that you use the midpoint formula to find the midpoint

Answer 28

never mind

Answer 29

It is possible to construct a midpoint, but it just says that they're finding the coordinates of the midpoint. To construct a midpoint:
Step 1: Create an arc from both endpoints using the same radius using a compass.
Step 2: Create a line that passes through the intersections.
Wait, that's for a bisector...still gives you the midpoint though...
You can just use a ruler for the midpoint.

Answer 30

B sounds like the most logical answer because if they weren't parallel then the slopes wouldn't be 0.

Answer 31

I concur...

Answer 32

and its obvious that the distance formula wasn't used so then its not C...

Answer 33

@gitahimart does B sound right?

Answer 34

Well apparently @ganeshie8 agrees with me since he gave me a medal XD

Answer 35

I got it right! Thank you all for all your help!

Answer 36

yes im with B

Answer 37

:)

Answer 38

I would try to give both of you a medal again but I can't :(