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Mathematics 7 Online
OpenStudy (anonymous):

I NEED help ..please help me with this I have a picture here

OpenStudy (anonymous):

|dw:1342920370986:dw| HOW DO I FIND THE ANGLE

OpenStudy (anonymous):

Anyone?

OpenStudy (anonymous):

Not the 90 degree one the other one

OpenStudy (anonymous):

Do you know SohCahToa?

OpenStudy (anonymous):

yea...but idk how to use it here

OpenStudy (anonymous):

So if i asked you to fill in the blank, what would you put in for "o" and "h" ? \[\sin \theta = {o \over h}\]

OpenStudy (anonymous):

i have no idea I KNOW ummm 3/5

OpenStudy (anonymous):

Correct!! Now, how would you go about solving for theta?? Have you learned about arcsin?

OpenStudy (anonymous):

no no i have not

OpenStudy (anonymous):

what is that?

OpenStudy (anonymous):

The arcsin function "undoes" the sin function. If you take the arcsin of both sides you can solve for theta. I'm trying to remember if there is another way of doing so without knowing the inverse trig functions.

OpenStudy (anonymous):

ohh ....can you still help me though?

OpenStudy (anonymous):

give me a minute to look something up.

OpenStudy (anonymous):

Ya, there is no way you can solve for the angle without being taught inverse trig functions. Did you miss a day of class or are you trying to do your homework early?

OpenStudy (anonymous):

Uggghh summer packet

OpenStudy (anonymous):

If you missed class, here's a good explanation of how to use the inverse trig functions. http://www.mathsisfun.com/algebra/trig-finding-angle-right-triangle.html

OpenStudy (anonymous):

is this it arcsin(y) = sin-1(y) = x + 2kπ

OpenStudy (anonymous):

not quite. the inverse trig functions work like this: \[\sin \theta = {o \over h}\] \[\sin^{-1} {o \over h} = \theta\] The sine and arcsine function are just an example. all trig functions have inverse functions.

OpenStudy (anonymous):

Does that help?

OpenStudy (anonymous):

i guess

OpenStudy (anonymous):

You know how whatever you do to one side of the equation you have to do to the other? Well the first equation has what we want but it's "inside" this sine function right? So this inverse trig function called, arcsin, or sin^(-1) would be taken on both sides of the equation. Since arcsin(sin(theta)) = theta, we get the second equation. Does that help any better?

OpenStudy (anonymous):

Here's a good, short video discribing it as well. PatrickJMT videos rock btw. :D http://patrickjmt.com/finding-an-angle-given-the-value-of-a-trigonometric-function-example-1/

OpenStudy (anonymous):

you could also just use the parathagoream thm x^2 + 4^2 =5^2

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