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Mathematics 19 Online
OpenStudy (anonymous):

g(x)=((x-2)(x-4)(x-6)(x-1))/(x-1)

OpenStudy (anonymous):

graph the following

OpenStudy (anonymous):

Do you notice a problem with the equation if x is equal to a certain number?

OpenStudy (anonymous):

stop asking me questions! i need u to do the problem !

OpenStudy (callisto):

@ferreiraalaura Welcome to OpenStudy. For your information, I'm sorry to tell you that it's *not* a site to seek for answers. It's a learning site. Please refer to our code of conduct at http://openstudy.com/code-of-conduct.

OpenStudy (callisto):

By the way, don't say ''i need u to do the problem!'' anymore.

OpenStudy (anonymous):

I agree that this is a learning site, but he has responded to all of my posts. None of his questions have helped me. If you want to help, your welcome to..

OpenStudy (callisto):

Hmm.. As I've checked, not all of your posts, just your previous one. And he would like to help you, though he thought you're not trying.. As for this question, first, you need to know the limit of the function. You know the function is undefined when denominator = 0. That's why @agentc0re asked you that question. Got it?

OpenStudy (anonymous):

yea i got it

OpenStudy (anonymous):

Thank you @Callisto @ferreiraalaura I know math can be frustrating at times. I'm just trying to point you in the right direction so you can solve it on your own which is the most important part.

OpenStudy (callisto):

To graph the function, simplify it first. But remember, the condition is denominator ≠ 0 Now, can you simplify g(x)?

OpenStudy (experimentx):

and look for zeros

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

2,4,and 6 are the zeros

OpenStudy (anonymous):

Actually, when I think of it, once she knows the restrictions, can't she just plug in x-values and get their respective y-values?

OpenStudy (callisto):

Yes, for some points, but perhaps that doesn't help much. It's not a straight line or parabola... @ferreiraalaura Have you learnt differentiation yet?

OpenStudy (anonymous):

@Calcmathlete Correct. Knowing where the denominator goes to zero is crucial. Then canceling it out with it's equivalent function on top. Then just plug in integer values to gain an aprox. graph.

OpenStudy (anonymous):

yea there is a hole at 1

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