Question

\[\iint\limits_D (2x-y)dA\]
\[D: \forall (x,y) \in x^2+y^2=4\]

Answer 1

D is bounded by the circle with center the origin and radius 2.

Answer 2

Ok, so what's dx and what's dy.?

Answer 3

heck, what are my limits?

Answer 4

\[\iint\limits_D (2x-y)dA\] \[D: \forall (x,y) \in x^2+y^2=4\]

Answer 5

hehe, didn't notice that...

Answer 6

it's a circle ...

Answer 7

yes, I stated that myself

Answer 8

??

Answer 9

mind explaining? I realize that since the limits are the same, you canmake the lower limit 0 by doubling, but this is a double integral...

Answer 10

x goes from -2 to +2 right, you just have to see how the limits of y goes in as x moves. also the above is quite incorrect.

Answer 11

that bottom should have been 0 instead of -2?

Answer 12

since you doubled up?