Question

If the velocity of a particle at time t is represented by the equation v(t) = 8t + 2, find the position of the particle at time 3 if the position at time 0 is 0.

Answer 1

dx/dt =8t+2
on integrating u get x=4t^2 +2t +c
at t=0 x=0 thus we have c=0
thus x=4t^2 +2t
at t=3 the position is 4(3)^2+2(3)=42

Answer 2

is distance(s) and position the same?

Answer 3

one can assume here

Answer 4

why did we have to integrate it? and what is x in the problem?

Answer 5

x is the position or disance in the problem...
v=dx/dt
so in order to get x we have to integrate v

Answer 6

ok..thanks a lot!!

Answer 7

welcome