Question

Please help

Answer 1

@waterineyes

Answer 2

Where??

Answer 3

\[\sqrt{x^{2}-7x+12}\]

Answer 4

Find the range?

Answer 5

Are you sure you want to find its range and not domain???

Answer 6

the domain?

Answer 7

can u explain what domain and range is?

Answer 8

I can here explain you about the domain only..

Answer 9

See your expression is:

\[f(x) = \sqrt{x^2 - 7x + 12}\]

For domain :

You should know the values inside the root cannot be 0 instead greater than or equal to zero..

So,

\[x^2 - 7x + 12 \ge 0\]

Can you factorize it??

Answer 10

Sorry cannot be negative..

Answer 11

(x-3)(x-4)

Answer 12

Yes so you got:"

\[(x-3)(x-4) \ge 0\]

Answer 13

yes

Answer 14

So you will get:

\[x \le 3\]
And:
\[x \ge 4\]

Answer 15

hw did u do that ? i need steps

Answer 16

Well I also don't know about this..
Ha ha ha..

Answer 17

i think we have to do it logically right..no equations involved, only that the root cannot be negative

Answer 18

Do you know the graph of Quadratic function...??

Answer 19

i hve learnt it..

Answer 20

cuts y axis at x =3 and x = 4