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Mathematics 8 Online
OpenStudy (swissgirl):

Prove: \[ (A-B) \cup (B-A) = (A \cup B) - (A \cap B) \]

OpenStudy (zzr0ck3r):

what is cup?

OpenStudy (swissgirl):

what did i do wrong?

OpenStudy (anonymous):

Union..

OpenStudy (swissgirl):

cup = union cap = intersection

OpenStudy (anonymous):

Cup is Union and cap is Intersection..

OpenStudy (anonymous):

I am writing it once again..

OpenStudy (swissgirl):

Why didnt it work :(((

OpenStudy (anonymous):

\[ (A-B) \cup (B-A) = (A \cup B) - (A \cap B)\]

OpenStudy (zzr0ck3r):

what is A/cupB

OpenStudy (zzr0ck3r):

ahh

OpenStudy (swissgirl):

i must have done smth wrong

OpenStudy (anonymous):

Do not use \{\} brackets instead use \[\] these brackets..

OpenStudy (zzr0ck3r):

sorry phone be back in a sec

OpenStudy (anonymous):

For this: Take any element that belongs to the set \((A-B) \cup (B-A)\) Suppose it as x.. So, \[x \in (A-B) \cup (B - A)\] Or you can say: \[x \in (A - B) \quad \color{green}{Or} \quad x \in (B - A)\] \[(x \in A \; and \; {x \cancel{\in} B)} \quad Or \quad (x \in B \; and \; x \cancel{\in} A)\] \[(x \in A \; Or \; { \in B)} \quad and \quad (x \cancel{\in} B \; Or \; x \cancel{\in} A)\] \[x \in (A \cup B) \; and \; x \cancel{\in} (A \cap B)\] \[x \in (A \cup B) - (A \cap B)\]

OpenStudy (swissgirl):

THHANNKKSSS GUYYSSSS

OpenStudy (anonymous):

|dw:1342982392324:dw| both (A-B)U(B-A) and (AUB)-(A^B) represent the same region. so both must be equal

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