Question

What are the asymptotes of (x^2/144)-(y^2/4)=1?
I think that it is y=1/6x?
Am I on the right track?

Answer 1

I think there are two asymptotes !

Answer 2

Okay...

Answer 3

12y=+or-2x

Answer 4

I dont understand...

Answer 5

I understand the ± but not the 12y and the 2x.

Answer 6

it's an equation of a hyperbola It should be "written" in this form
\[(x/a)^2-(y/b)^2=\pm 1\]
then the asymptotes are \[ay=\pm bx\]

Answer 7

\[x^2/144=(x/12)^2\]

Answer 8

Did you understand now ?