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What are the asymptotes of (x^2/144)-(y^2/4)=1? I think that it is y=1/6x? Am I on the right track?
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I think there are two asymptotes !
Okay...
12y=+or-2x
I dont understand...
I understand the ± but not the 12y and the 2x.
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it's an equation of a hyperbola It should be "written" in this form \[(x/a)^2-(y/b)^2=\pm 1\] then the asymptotes are \[ay=\pm bx\]
\[x^2/144=(x/12)^2\]
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