Question

3x^2 + 22x - 16 = 0 solve by factoring

Answer 1

I am relatively good at these but I am stuck.

Answer 2

the easy way is multiply 3 and - 16 gives -48.... find the factors of -48 that add to 22

-2 and 24

then its

\[\frac{(3x - 2)(3x + 24)}{3} = \frac{3(3x -2)(x + 8)}{3}\]

cancel the common factor of 3

leaves (3x -2)(x + 8)

Answer 3

3x^2+24x-2x-16=0
3x(x+8)-2(x+8)=0
(3x-2)(x+2)=0

Answer 4

thank you both so much. I am really grateful

Answer 5

(3x-2)(x+*)

Answer 6

x+8

Answer 7

Wait, I need to solve to zero, I keep coming up with 2/3 and -8 its not right I don't think. Can you help me finish it off?

Answer 8

what answer is given for this

Answer 9

the solution of 2/3 and -8 is correct

Answer 10

when I check it, it comes out all wacky
. Maybe it's just me

Answer 11

could we go through that part together please? If you have time

Answer 12

yua that ans is correct

Answer 13

ok... 3(-8)^2 + 22(-8) - 16 = 192 - 176 - 16 = 0

and 3(2/3)^2 + 22(2/3) - 16 = 4/3 + 44/3 - 16 = 48/3 - 16 = 0

both solutions work

Answer 14

W.O.W. I feel silly, I had simply forgotten to square. Thank you so much for your help.

Answer 15

hope it helps