Which factor can you cancel from the numerator and denominator to simplify 8-2x/3x-12? [Hint: (a−x) = − (x − a)]
can you notice a common factor in the numerator between the terms 8 and 2x?
2
good, so can you write the numerator with the 2 taken out as a factor?
sorry that kinda confused me
ok - you correctly found that 2 is a common factor between 8 and 2x, this means we can factor the numerator as follows:\[8-2x=2(4-x)\]agreed?
oh yes. i agree
good - now try the same thing with the denominator - what is common between 3x and 12?
3 so 2(x-4)
*3
perfect! so now you end up with:\[\frac{8-2x}{3x-12}=\frac{2(4-x)}{3(x-4)}\]next, try and make use the hint given to you in the question.
so i cold cancel out the 4's?
no, what you need to do is notice that:\[(4-x)=-(x-4)\]
do you understand that?
not really
ok, let me try to explain...
ok
\[-(x-4)=-x-(-4)=-x+4=4-x\]does it make sense now?
yes
ok, so if we use this fact, then we can substitute:\[(4-x)=-(x-4)\]into out fraction to get:\[\frac{8-2x}{3x-12}=\frac{2(4-x)}{3(x-4)}=\frac{-2(x-4)}{3(x-4)}\]
make sense?
yes
ok now you should be able to see that we can cancel out \((x-4)\) from numerator and denominator.
makes sense now! thanks so much! tremendous help!
yw :)
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