Question

Challenge:-
The person who will find the answer will be given a medal !

Answer 1

\[\Large{\text{How to find the no. of diagonals in any Polygon???}}\]

Answer 2

umber of diagonals = n(n-3)/2

Answer 3

Suppose a polygon has n vertices (and sides).
From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex.
Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals.
number of diagonals = n(n-3)/2

Read more: http://wiki.answers.com/Q/What_is_the_formula_for_the_number_of_diagonals_in_a_polygon#ixzz21OPHqcB6

Answer 4

HAHAHAHA
@walac found the answer first :)
& given a medal ;)

Answer 5

@J.L. found the answer from the same reference I did.

Answer 6

but u were fast ;)

Answer 7

hahaha, I was... But we are not in a competition, this is a collaboration group, but sometimes a little fun won't kill anyone...

Answer 8

yes right it was fun