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OpenStudy (anonymous):

Oxidation for COH2 and FeBr2

OpenStudy (anonymous):

@zepp come here

OpenStudy (anonymous):

@Outkast3r09 come here

OpenStudy (anonymous):

rawr!!!

OpenStudy (anonymous):

dont bite me! :O

OpenStudy (anonymous):

bite the question :)))

OpenStudy (anonymous):

FeBr2 what is the oxidation of Bromine?

OpenStudy (anonymous):

how would i know? o_0

OpenStudy (anonymous):

well for one the group number helps you figure out the charge

OpenStudy (anonymous):

the charge of Br is -1

OpenStudy (anonymous):

alright and you have 2 , so -2 charge.. if you name Fe oxidation as x x-2=0

OpenStudy (anonymous):

oh so it's 2 and -2 ?

OpenStudy (anonymous):

2 and -1

OpenStudy (anonymous):

ehh wtf.. o_0

OpenStudy (anonymous):

you just the oxidation of Bromine not \[Br_2\]

OpenStudy (anonymous):

\[br_2\] charge is -2 where as \[Br\]has a -1

OpenStudy (anonymous):

i see..

OpenStudy (anonymous):

what about COH2 ?

OpenStudy (anonymous):

i know O = -2 charge, and H = -1 charge

OpenStudy (anonymous):

alright so you know O=-2 and H=-1 but you have 2 H's so therefore you have a -2 charge

OpenStudy (anonymous):

the charge of C =x x-2-2=0

OpenStudy (anonymous):

x=4 C=+4

OpenStudy (anonymous):

so 4,-2,-1 ?

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