Question

factor completely 2x2-2x-12

Answer 1

\[2x ^{2}-2x-12\]

Answer 2

(x+_)(x-_)

Answer 3

Just fill in the blanks

Answer 4

I think you forgot a step there...
\[2x^2 - 2x - 12 \implies 2(x^2 - x - 6) \implies 2(x + _)(x + _)\]Now find 2 factors of -6 that add up to -1 and place them in those spots.

Answer 5

@Calcmathlete the signs would be +/-

Answer 6

oops... lol
That should say \[2(x + ? )(x + ? )\]
@J.L. Actually, since I asked for the factors of it, you would get a negative and a positive. If I did a + and a -, then this qould've happened.
\[2(x - (-?)(x + ?)\]which turns to \[2(x + ?)(x + ?)\]

Answer 7

the whole factorization would be
2(x+3)(x-2)

Answer 8

So +/- makes sense @Calcmathlete

Answer 9

Ok. Look at what happens using my way.
2(x + (-3))(x + 2) -> 2(x - 3)(x + 2)
The factors would've been -3 and 2 which make sense when using + :)

Answer 10

Yea you're right for the number placings I didn't realize the x is negative
Still would be +/- because of the -3 unless you write (x+-3) which I get plain confused by

Answer 11

lol alright. The reason I did that is because 2(x - )(x + ) would only work if you took the absolute value of the factors.

Answer 12

Since there is a negative in the normal factors, it would be incorrect if I used that.

Answer 13

Have you realized that the person asking this question isn't even online?

Answer 14

Yeah...sometimes they just go offline and hope that there is an answer by the time they get back.

Answer 15

No that is not the case, my phone died. And I just got back on.

Answer 16

And honestly I have no clue as to what the answer is I'm not good with math. Thanks for the help though.