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Mathematics 19 Online
OpenStudy (anonymous):

How do you simplify this?

OpenStudy (anonymous):

\[x ^{2}+2x-15/x ^{2}+3x-10\]

OpenStudy (zepp):

You'd have to factor the numerator and the denominator

OpenStudy (lgbasallote):

Hint: \[\frac{x^2 + 2x - 15}{x^2 + 3x - 10} \implies \frac{(x+5)(x-3)}{(x+5)(x-2)}\]

OpenStudy (anonymous):

I don't understand what you have to do after that

OpenStudy (zepp):

\[\large \frac{(x+5)}{(x+5)}*\frac{(x-3)}{(x-2)}=1*\frac{(x-3)}{(x-2)}\]

OpenStudy (lgbasallote):

\[\frac{\cancel{(x+5)}(x-3)}{\cancel{(x+5)}(x-2)}\]

OpenStudy (lgbasallote):

that's what happens

OpenStudy (anonymous):

by saying \[x2+2x−15/x2+3x−10\] did you mean \[(x2+2x−15)/(x2+3x−10) \]?

OpenStudy (anonymous):

Really sorry, but I'm still a bit confused.

OpenStudy (anonymous):

@lexbryan yes

OpenStudy (anonymous):

then @lgbasallote is correct.

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