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How do you simplify this?
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\[x ^{2}+2x-15/x ^{2}+3x-10\]
You'd have to factor the numerator and the denominator
Hint: \[\frac{x^2 + 2x - 15}{x^2 + 3x - 10} \implies \frac{(x+5)(x-3)}{(x+5)(x-2)}\]
I don't understand what you have to do after that
\[\large \frac{(x+5)}{(x+5)}*\frac{(x-3)}{(x-2)}=1*\frac{(x-3)}{(x-2)}\]
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\[\frac{\cancel{(x+5)}(x-3)}{\cancel{(x+5)}(x-2)}\]
that's what happens
by saying \[x2+2x−15/x2+3x−10\] did you mean \[(x2+2x−15)/(x2+3x−10) \]?
Really sorry, but I'm still a bit confused.
@lexbryan yes
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then @lgbasallote is correct.
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