Which of the following ordered pairs is not a solution to the inequality y (less than or equal to) -3x - 5? A) (-4, 0) B) (0, 0) C) (-3, 0) D) (-2, 0)
try to plug-in the options given.
if it does not satisfy the sense of the inequality, hence, it is not a solution to that inequality.
\[y \le -3x - 5\] Or: \[3x + y \le -5\] Three times the x value + y value should be less than or equal to 1.. Try it from choices given...
First one
Really???
\[y≤−3x−5\]since all of the answer choices have y=0 we can simply plug that in \[0≤−3x−5\]
It's not the answer I'm responding to your question @waterineyes
So basically we are asking ourselves for what value of x will \[-3x-5\] be greater than zero
I have not asked any question @Romero I said to go this way and not asked can you go this way...
We know that x has to be a negative in order to get an answer
that will agree with the inequality. Which one of the answers doesn't have x as a negative (x,y)
A) (-4, 0) B) (0, 0) C) (-3, 0) D) (-2, 0) \[(x,y)\] which answer has a first number that is not a negative?
b
great if you need to know why that's the answer go reread the posts I made.
You are correct good job!
alright i will
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