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Find h'(2) given that f(2)=-1, f'(2)=4, g(2)=1 and g'(2)=-5
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its upside down
For (a), h(x) = 5f(x) + 2g(x) Diff. both sides w.r.t. x h'(x) = 5f'(x) + 2g'(x) So, h'(2) = 5f'(2) + 2g'(2) Time to sub. values and get your answer. Got it?
@cunninnc
H(x) = 5 f'(x) + 2g'(x)
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H'(2)= 5x4-2x5=10
H'(x) = f(x).g'(x) + f'(x).g(x)
H'(x)= 4x2+ -1x-5 = 13
h'(x) = 1/ f(x)
1/f(x) . F'(x)= 4/-2=-2
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