Question

Calculates the acceleration of a body starting from rest and has a speed of 20m / s after traveling 100m.
Help please!

Answer 1

a = v^2 \r
answer=4 i think

Answer 2

but above eq is for the body moving in circular path!

Answer 3

ok assume constant acceleration
using third equation
\[2as=v^2 _{f}-vi^2_{i}\]
here a=acceleration
vf=final speed
s=distance covered
vi=initial velocity
in the problem given data is
s=100m
vi=0 (bcz starting frm rest)
vf=20m/s
put in above equation
\[a=\frac{v^2_{f}}{2s}\]
\[a=\frac{20m^2}{2(100m)}\]
i hope you can do this now

Answer 4

\[a=\frac{(20m/s)^2}{2(100m)}\]

Answer 5

@sami-21 this equation is for body moving uniformaly!

Answer 6

x=xo+vo.t+1/2.a.t2
kia hum yeh wala formula use nhi kr sakhty
@sami-21

Answer 7

@ali110 look at first line of my response .

Answer 8

muskan dear no because hamein time nahi given hai
hamne sirf given info use karni hai

Answer 9

@Muskan no because time is not given :)

Answer 10

2as=v2f−vi2i
yeh formula meri book may hai ..

2as?? means

Answer 11

2 *aceeleration *distance

Answer 12

nhi hai *****

Answer 13

muskan y??

Answer 14

2as is simply product of acceleration and distance it is in the standard formula .
does not represent any physical Quantity.

Answer 15

{s} = displacement

{u} = initial velocity

{v} = final velocity

{a} = uniform acceleration

Answer 16

okkk...
Thanks Friends