Question

let f(x)=(6x-7)^5 find f"(x)

Answer 1

differentiate it 2 times

Answer 2

is that f'(x) as in the derivative?
f'(x)=df/dx=5(6x-7)^4 * (6)

Answer 3

f(x)=(6x-7)^5
f'(x)=5(6)(6x-7)^4 = 30(6x-7)^4
f''(x)= diff. f'(x)

Answer 4

he says he ahs problem with the last step only he has reached till here

Answer 5

DOUBLE PRIME OH I DIDN'T SEE THAT LOL
so f'(x)=30(6x-7)^4
then f''(x)=30*4(6x-7)^3=120(6x-7)^3 by chain rule again

Answer 6

What will you get when you multiply the coefficient with the power @qasaali

Answer 7

@qasaali if you will not interact with us then we can't help you..

What we are saying just give a reply to that..

Answer 8

I said to interact here @qasaali not in the chat box..

Answer 9

ow yeah!!!!!!!!!!!!!!!!

Answer 10

Simply tell me what is coefficient and what is the power here after taking first derivative..

Answer 11

u coefficient the is variables which are found infront of any expression, and Power is the numbers which are found at the top of varaibles or expressions as
for example X^2............................... X^3 AND ETC

Answer 12

You have the concept but you are not applying here that concept:

See:

\[f'(x) = 30(6x-7)^4\]

Here tell me what is the value of coefficient and what is power here..

Answer 13

Here the coefficient is 30.............................................. and the Power is the 4 up there

Answer 14

water got the point

Answer 15

Yes you are right..
Then multiply both of them:

30*4 = ??

Are you helping me or I am helping you??

Forget..

Just multiply them and tell me what you got..

Answer 16

u r helping me

Answer 17

i need an other help man
i will post c it