Question

differentiate

\[e^(x+(e^x+e^x+...)) = y\]

Answer 1

\( ln y =x+e^{x}+e^{x}+... \) ? o.O

Answer 2

its actually e^(x+(e^x+e^x+....)) = y

Answer 3

ok then

Answer 4

but what kind of function it is ?

Answer 5

i don't know..

its a question u have to answer for.......

Answer 6

\[\Large e^{x + (e^x + e^x + \cdots )} = y\]

Answer 7

is that it?

Answer 8

yes

Answer 9

\(y'=(1+e^{x}+e^{x}+...)(e^{x+e^x+e^x+...}) \)

Answer 10

let \[e^x + e^x + \cdots = a\]

\[e^{x+a} = y\]
\[x+a = \ln y\]
\[1 + a = \frac{y'}{y}\]
\[\Large y' = e^{x + (e^x + e^x + \cdots)} (1 + e^ x + e^x + \cdots)\]

Answer 11

Ya that is right

Answer 12

thanks everyone