simplify (4n(n+1)(2n+1)/6)+n
you may use foil method on (n+1)(2n+1) first.
Check it once more...
(4(2n^2+3n+1)/6)+n
4?? or 4n???
It is 4n outside the brackets: You have only solved for (n+1)(2n+1)
(4(2n^2+3n+1)/6)+n wrong.. it is 4n outside.. Yes or no??
See go step by step tell me what do you get: (n+1)(2n+1) = ?? Solve this first..
2n^2+3n+1
Yes... Now do this: \(4n(2n^2 + 3n + 1)\) = ??
You are right don't mind.. My mind is mad..
Yes you are right dear... Now solve that what I have written there..
8n^3+12n^2+4n
Yes so 4n not 4.. now write the entire what you get..
can I write that as (8n^3/6)+(12n^2/6)+(4n/6)
\[\frac{8n^3 + 12n^2 + 4n}{6} + n \implies \frac{8n^3 + 12n^2 + 4n + 6n}{6}\] Solve this..
Are you getting this step??? You can also write what you did above that is also correct.. It is all about taking the LCD..
right
(4n^3/)3+(2n^2)+(5n/3)
Absolutely right dear...
Or you can leave the result as such like this there is nothing wrong in this: \[\implies \frac{8n^3 + 12n^2 + 10n}{6} \implies \frac{2n^3 + 6n^2 + 5n}{3}\]
thanks
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