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OpenStudy (anonymous):
simplify (4n(n+1)(2n+1)/6)+n
14 years ago
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OpenStudy (anonymous):
you may use foil method on (n+1)(2n+1) first.
14 years ago
OpenStudy (anonymous):
Check it once more...
14 years ago
OpenStudy (anonymous):
(4(2n^2+3n+1)/6)+n
14 years ago
OpenStudy (anonymous):
4??
or 4n???
14 years ago
OpenStudy (anonymous):
It is 4n outside the brackets:
You have only solved for (n+1)(2n+1)
14 years ago
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OpenStudy (anonymous):
(4(2n^2+3n+1)/6)+n wrong..
it is 4n outside..
Yes or no??
14 years ago
OpenStudy (anonymous):
See go step by step tell me what do you get:
(n+1)(2n+1) = ??
Solve this first..
14 years ago
OpenStudy (anonymous):
2n^2+3n+1
14 years ago
OpenStudy (anonymous):
Yes...
Now do this:
\(4n(2n^2 + 3n + 1)\) = ??
14 years ago
OpenStudy (anonymous):
You are right don't mind..
My mind is mad..
14 years ago
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OpenStudy (anonymous):
Yes you are right dear...
Now solve that what I have written there..
14 years ago
OpenStudy (anonymous):
8n^3+12n^2+4n
14 years ago
OpenStudy (anonymous):
Yes so 4n not 4..
now write the entire what you get..
14 years ago
OpenStudy (anonymous):
can I write that as (8n^3/6)+(12n^2/6)+(4n/6)
14 years ago
OpenStudy (anonymous):
\[\frac{8n^3 + 12n^2 + 4n}{6} + n \implies \frac{8n^3 + 12n^2 + 4n + 6n}{6}\]
Solve this..
14 years ago
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OpenStudy (anonymous):
Are you getting this step???
You can also write what you did above that is also correct..
It is all about taking the LCD..
14 years ago
OpenStudy (anonymous):
right
14 years ago
OpenStudy (anonymous):
(4n^3/)3+(2n^2)+(5n/3)
14 years ago
OpenStudy (anonymous):
Absolutely right dear...
14 years ago
OpenStudy (anonymous):
Or you can leave the result as such like this there is nothing wrong in this:
\[\implies \frac{8n^3 + 12n^2 + 10n}{6} \implies \frac{2n^3 + 6n^2 + 5n}{3}\]
14 years ago
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OpenStudy (anonymous):
thanks
14 years ago
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