Question

How do you simplify this..?

Answer 1

\[(x ^{2}+6x-16/3x ^{2}-9x)\times(6x-18/x ^{2}-x-2)\]

Answer 2

It is a fraction

Answer 3

\[\frac{x^2 + 6x - 16}{3x^2 - 9x} \times \frac{6x - 18}{x^2 - x - 2}\]

Answer 4

Is that the problem?

Answer 5

yes

Answer 6

\[\frac{x^2 + 6x - 16}{3x^2 - 9x} \times \frac{6x - 18}{x^2 - x - 2} \implies \frac{(x + 8)(x - 2)}{3x(x - 3)} \times \frac{6(x - 3)}{(x - 2)(x + 1)}\]Can you figure the rest out? (Hint: cross cancel)

Answer 7

(x+8/3x)*(6/x+1)

Answer 8

Very close.
\[\frac{(x + 8)(x - 2)}{3x(x - 3)} \times \frac{6(x - 3)}{(x - 2)(x + 1)} \implies \frac{x + 8}{3x} \times \frac{6}{x + 1} \implies \frac{x + 8}{\cancel3x} \times \frac{\cancel62}{x + 1}\]\[\implies \frac{x + 8}{x} \times \frac{2}{x + 1} \implies ?\]

Answer 9

Hold on, I'm going to look at your work for a second

Answer 10

What do you from then on? Isn't that at its simplified point?

Answer 11

Alright. All you have to do now is just multiply the fractions.
\[\frac{x + 8}{x} \times \frac{2}{x + 1} \implies \frac{(x + 8) \times 2}{x \times (x + 1)} \implies ?\]

Answer 12

2x+16/x+x^2

Answer 13

Yup. You can also leave it as \(\LARGE \frac{2(x + 8)}{x(x + 1)} \space or \space \frac{2x + 16}{x^2 + x}\)

Answer 14

Oh, and one more question!

Answer 15

Sure :)

Answer 16

How do you type up your equations in fraction form?

Answer 17

Erase the spaces in between the \ [ and the \ ] when you want to try it.
\ [\frac{ }{ } \ ]
Just put what you want in the numerator and denominator in that order in those braces

Answer 18

Thank you!

Answer 19

np :)

Answer 20

It takes a little practice though, so good luck.

Answer 21

Haha, thanks :)