Question

calc help, integral x/(sqrt(3-2x^(2)-x^(4))

Answer 1

\[\large{\int{\frac{x}{\sqrt{3-2x^2-x^4}}}}\]
Just for ease :)

Answer 2

gracias lol

Answer 3

The expression in the radical is simply a polynomial of x^2, so I'd let u=x^2.

Answer 4

so far i got to \[\int\limits\limits_{n/a}^{n/a} x/\sqrt(4-(x ^{4}+1)^{2})\]

Answer 5

thats (x^2+1)^2

Answer 6

^

Answer 7

its better to let \( u=1+x^2 \) i think :D

Answer 8

came to 1/2 integral (du)/sqrt(4-(u)^2

Answer 9

I would use arcsin integral correct?

Answer 10

u/2 no ?! @mukushla

Answer 11

sorry a little typo \(\large \frac{1}{2} \arcsin \frac{u}{2} \)

Answer 12

and u r Quite Right @Ink412

Answer 13

1/2 arcsin (u or 1+ (u)^2/ 2) + c?

Answer 14

u mean 1+x^2 ?

Answer 15

yeah lol

Answer 16

:)

Answer 17

thanks for the help

Answer 18

yw :)